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ICSE Class X Math 2015 Paper

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Three vertices of a parallelogram ABCDA B C D taken in order are A(3,6),B(5,10)A(3,6), B(5,10) and C(3C(3, 2) find:
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Question : 9 of 52
Marks: +1, -0
equation of side ABA B of the parallelogram ABCDA B C D .
Solution:  
Equation of ABAB :
y−y1  =  y2−y1x2−x1(x−x1)y-y_1\;=\;\frac{y_2-y_1}{x_2-x_1} (x-x_1)
y−6  =  10−65−3(x−3)y-6\;=\;\frac{10-6}{5-3}(x-3)
y−6  =  42(x−3)y-6\;=\;\frac{4}{2}(x-3)
y−6  =2x−6y-6\;=2 x-6
2x−y  =02 x-y\;=0
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