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ICSE Class X Math 2016 Paper

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In the given figure below, ADA D is a diameter. OO is the centre of the circle. ADA D is parallel to BCB C and ∠CBD=32∘\angle C B D=32^{\circ}. Find:
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Question : 10 of 57
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∠AOB\angle AOB
Solution:  
∠AOB=2∠ODB\angle AOB = 2 \angle ODB
(angle at the centre is twice the angle at remaining circumference)
=2×32=64∘=2 \times 32=64^{\circ}
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