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ICSE Class X Math 2016 Paper

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Draw a line AB=5 cmA B = 5 \text{ cm}. Mark a point CC on ABA B such that AC=3 cmA C = 3 \text{ cm}. Using a ruler and aa compass only, construct :
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Question : 34 of 57
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A circle of radius 2.5 cm2.5 \text{ cm}, passing through AA and CC.
Solution:  
Steps of Construction :
(1) Draw line AB=5 cmAB=5 \text{ cm}
(2) From ABAB cut AC=3 cmAC=3 \text{ cm}.
(3) Draw right bisector of A CA\,C.
(4) Taking AA as centre and AO=2.5AO=2.5 cm cm\text{cm}\ \text{cm} as radius, draw an arc to meet the right bisector of ACAC at OO.
(5) Taking OO as the centre and AO=AO= 2.5 cm2.5 \text{ cm} as radius, draw a circle, which passing through A&CA \& C.
(6) Join BO.
(7) Draw right bisector of BOBO, which cuts BOBO at PP.
(8) Taking PP as centre and O PO\,P as radius, draw a circle which cuts old circle at R&TR \& T.
(9) Join BR and BT.
These are required tangents.
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