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ICSE Class X Math 2017 Paper

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Question : 30 of 31
Marks: +1, -0
△PQR\triangle PQR is a triangle. SS is a point on the side QRQR of △PQR\triangle PQR such that ∠PSR=∠QPR\angle PSR = \angle QPR.
Given QP=8 cm, PR=6 cmQP = 8\ \mathrm{cm},\ PR = 6\ \mathrm{cm} and SR=3 cmSR = 3\ \mathrm{cm}
(i) Prove △PQR∼△SPR\triangle PQR \sim \triangle SPR
(ii) Find the length of QRQ R and PS
(iii) area of △PQRarea of △SPR\frac{\text{area of }\triangle PQR}{\text{area of }\triangle SPR}
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