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ICSE Class X Math 2018 Paper

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Question : 17 of 32
Marks: +1, -0
If A=[2357],B=[0417]A=\begin{bmatrix} 2 & 3 \\ 5 & 7 \end{bmatrix}, B=\begin{bmatrix} 0 & 4 \\ -1 & 7 \end{bmatrix} and C=[1014]C=\begin{bmatrix} 1 & 0 \\ -1 & 4 \end{bmatrix}, find AC+B210CAC + B^2 - 10C.
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