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NCERT Class XI Chemistry Classification of Elements and Periodicity in Properties Solutions

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Question : 30 of 40
Marks: +1, -0
Assign the position of the element having outer electronic configuration
(i) ns2np4ns^2np^4 for n = 3
(ii) (n – 1) d2ns2d^2ns^2 for n = 4, and
(iii) (n – 2) f7f^7 (n – 1) d1ns2d^1ns^2 for n = 6, in the periodic table.
Solution:  
(i) ns2np4ns^2 np^4 For n = 3 ; outer electronic configuration = 3s23p43s^2 3p^4
∴ The element will be in 3rd period, 16th group and p-block (Sulphur).
(ii) (n – 1) d2ns2d^2 ns^2
For n = 4 ; outer electronic configuration = 3d24s23d^2 4s^2
∴ The element will be in 4th period, 4th group and d-block (Titanium).
(iii) (n – 2) f7f^7 (n – 1) d1ns2d^1ns^2
For n = 6 ; the outer electronic configuration is 4f75d16s24f^7 5d^1 6s^2.
∴ The element will be in 6th period, 3rd group and f-block (Gadolinium).
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