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NCERT Class XI Chemistry Hydrocarbons Solutions

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Question : 20 of 25
Marks: +1, -0
How would you convert the following compounds into benzene?
(i) Ethyne
(ii) Ethene
(iii) Hexane
Solution:  
(i) HC≡CHEthyne\underset{\text{Ethyne}}{\mathrm{HC≡CH}} →873 Kred hot iron tube\xrightarrow[873\,\text{K}]{\text{red hot iron tube}}
(ii) CH2=CH2Ethene\underset{\text{Ethene}}{\mathrm{CH_2=CH_2}} →CCl4Br2\xrightarrow[\mathrm{CCl}_4]{\mathrm{Br}_2} ∣BrCH2−∣BrCH2\underset{\mathrm{CH}_2}{\underset{\mathrm{Br}}{\vert}} - \underset{\mathrm{CH}_2}{\underset{\mathrm{Br}}{\vert}} →Δalc. KOH\xrightarrow[\Delta]{\text{alc. KOH}} CH2=CHBr\mathrm{CH_2=CHBr} →NaH2/liquid NH3,196 K\xrightarrow{\mathrm{NaH}_2/\mathrm{liquid\ NH}_3, 196\,\text{K}} HC≡CH\mathrm{HC≡CH} →red hot iron tube,873 K\xrightarrow{\text{red hot iron tube}, 873\,\text{K}}
(iii) C6H14Hexane\underset{\text{Hexane}}{\mathrm{C_6H_{14}}} →773 K,10−20 atmCr2O3/V2O5/Mo2O3\xrightarrow[773\,\text{K}, 10-20\,\text{atm}]{\mathrm{Cr}_2\mathrm{O}_3/\mathrm{V}_2\mathrm{O}_5/\mathrm{Mo}_2\mathrm{O}_3}
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