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NCERT Class XI Chemistry Hydrocarbons Solutions

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Question : 1 of 25
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How do you account for the formation of ethane during chlorination of methane?
Solution:  
Initiation : The chlorination of methane follows a free radical mechanism. Initially, by the action of heat or sunlight on Cl2, the Cl – Cl bond breaks.
Cl−Cl↷↻\mathrm{Cl}-\overset{\underset{↻}{↷}}{\mathrm{Cl}} → Cl.+Cl.\overset{.}{\mathrm{Cl}}+\overset{.}{\mathrm{Cl}}
Propagation : This produces two free radicals which abstract a hydrogen free radical from the methane molecule thereby generating a methyl free radical.
Cl.+H−CH3↶↺\overset{.}{\mathrm{Cl}} + \mathrm{H}-\overset{\underset{↺}{↶}}{\mathrm{CH}_3} → H−Cl+CH3∙ methyl radical.\mathrm{H-Cl}+\overset{\bullet}{\mathrm{CH}_3}\ \text{methyl radical}.
Termination : Now this methyl free radical may either combine with a chlorine free radical to form the desired product – chloromethane or may combine with another methyl radical to form an ethane molecule.
CH3.+Cl.\overset{.}{\mathrm{CH}_3}+\overset{.}{\mathrm{Cl}} → CH3Clmethyl chloride\underset{\text{methyl chloride}}{\mathrm{CH}_3\mathrm{Cl}}
or CH3.+CH3.\overset{.}{\mathrm{CH}_3}+\overset{.}{\mathrm{CH}_3} → CH3−CH3ehtane\underset{\text{ehtane}}{\mathrm{CH}_3-\mathrm{CH}_3}
This is how ethane is generated during the chlorination of methane.
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