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NCERT Class XI Chemistry Organic Chemistry Some basic principles and Techniques Solutions

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Question : 6 of 40
Marks: +1, -0
Draw formulas for the first five members of each homologous series beginning with the following compounds.
(a) H–COOH (b) CH3COCH3CH_3COCH_3 (c) H–CH=CH2H–CH =CH_2
Solution:  
(a) : HCOOH
The given compound is formic acid (a carboxylic acid) and the first five members of the carboxylic acid series are :
(1) HCOOH
(2) CH3COOHCH_3COOH
(3) CH3CH2COOHCH_3CH_2COOH
(4) CH3CH2CH2COOHCH_3CH_2CH_2COOH
(5) CH3CH2CH2CH2COOHCH_3CH_2CH_2CH_2COOH
(b) : CH3COCH3CH_3COCH_3
The given compound, propanone, is a ketone and the first five members of the ketone series are :
(1) CH3COCH3CH_3COCH_3
(2) CH3CH2COCH3CH_3CH_2COCH_3
(3) CH3CH2CH2COCH3CH_3CH_2CH_2COCH_3
(4) CH3CH2CH2CH2COCH3CH_3CH_2CH_2CH_2COCH_3
(5) CH3CH2CH2CH2CH2COCH3CH_3CH_2CH_2CH_2CH_2COCH_3
(c) : CH2=CH2CH_2= CH_2
Ethene is an alkene and the first five members of the alkene series are :
(1) CH2=CH2CH_2 =CH_2
(2) CH3–CH=CH2CH_3–CH =CH_2
(3) CH3CH2—CH=CH2CH_3CH_2 —CH =CH_2
(4) CH3CH2CH2—CH=CH2CH_3CH_2CH_2—CH =CH_2
(5) CH3CH2CH2CH2−CH=CH2CH_3CH_2CH_2CH_2-CH= CH_2
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