Compare the relative stability of the ...

NCERT Class XI Chemistry Solutions

Question : 36 of 40

Marks: +1, -0

Compare the relative stability of the following species and indicate their magnetic properties;

\mathrm{O}_2

\mathrm{O}_2^{+}

\mathrm{O}_2^{-}

(superoxide),

\mathrm{O}_2^{2-}

(peroxide).

Solution:

Species	Total electrons	Configuration	Bond order	Magnetic character
$\mathrm{O}_2$	16	$KK\sigma(2s)^2 \sigma^(2s)^2\sigma(2p_z)^2 \pi(2p_x)^2$ = $\pi(2p_y)^2\pi^(2p_x)^1$ = $\pi^*(2p_y)^1$	$\frac{8-4}{2}$ = 2.0	Paramagnetic
$\mathrm{O}_2^{+}$	15	$KK\sigma(2s)^2 \sigma^(2s)^2\sigma(2p_z)^2 \pi(2p_x)^2$ = $\pi(2p_y)^2\pi^(2p_x)^1$	$\frac{8-3}{2}$ = 2.5	Paramagnetic
$\mathrm{O}_2^{-}$	17	$KK\sigma(2s)^2 \sigma^(2s)^2\sigma(2p_z)^2 \pi(2p_x)^2$ = $\pi(2p_y)^2\pi^(2p_x)^2$ = $\pi^*(2p_y)^1$	$\frac{8-5}{2}$ = 1.5	Paramagnetic
$\mathrm{O}_2^{2-}$	18	$KK\sigma(2s)^2 \sigma^(2s)^2\sigma(2p_z)^2 \pi(2p_x)^2$ = $\pi(2p_y)^2\pi^(2p_x)^2$ = $\pi^*(2p_y)^2$	$\frac{8-6}{2}$ = 1.0	Diamagnetic

∴ Relative order of stability is

\mathrm{O}^{2+}\% >

O_2

>

O_2^{–}

>

O_2^{2–}$.

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