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NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

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Question : 36 of 36
Marks: +1, -0
Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2)(MnO_2) with aqueous hydrochloric acid according to the reaction
4HCl(aq)+MnO2(s)4HCl_(aq) + MnO_{2(s)} → 2H2O(l)+MnCl2(aq)+Cl2(g)2H_2O_(l) + MnCl_{2(aq)} + Cl_{2(g)}
How many grams of HCl react with 5.0 g of manganese dioxide?
Solution:  
4HCl(aq)↙4 mole or 146g+MnO2(s)1 mole or 87g{4HCl}_{(aq)}\underset{\text{4 mole or 146g}}{\swarrow} + {MnO}_{\underset{\text{1 mole or 87g}}{2(s)}} → 2H2O(l)+MnCl2(aq)+Cl2(g)2H_2O_(l) + MnCl_{2(aq)} + Cl_{2(g)}
87 g of MnO2MnO_2 reacts with HCl = 146 g
5 g of MnO2MnO_2 reacts with HCl = 146×5/87{146×5}/{87} = 9.39 ≈ 8.40 g
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