Test Index

NCERT Class XI Chemistry Some Basic Concepts of Chemistry Solutions

© examsnet.com
Question : 9 of 36
Marks: +1, -0
Calculate the atomic mass (average) of chlorine using the following data :
% Natural abundance Molar mass
35Cl\,{}^{35}\mathrm{Cl} 75.77 34.9689
37Cl{}^{37}\mathrm{Cl} 24.2336.9659
Solution:  
The atomic mass (average) of chlorine
= 75.77×34.9689+24.23×36.965975.77+24.23\frac{75.77\times 34.9689 + 24.23\times 36.9659}{75.77+24.23} = 2649.59+895.68100\frac{2649.59+895.68}{100} = 3545.27100\frac{3545.27}{100} = 35.45 u
© examsnet.com
Go to Question: