Test Index

NCERT Class XI Chemistry States of Matter Solutions

© examsnet.com
Question : 4 of 23
Marks: +1, -0
At 0°C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide?
Solution:  
MoxideM_{\text{oxide}} = doxideRTPoxide\frac{d_{\text{oxide}}RT}{P_{\text{oxide}}} ... (1)
MN2M_{\mathrm{N}_2} = dN2RTPN2\frac{d_{\mathrm{N}_2}RT}{P_{\mathrm{N}_2}} ... (2)
Dividing equation (1) by equation (2) gives
MoxideMN2\frac{M_{\text{oxide}}}{M_{\mathrm{N}_2}} = doxideRT×PN2Poxide×dN2\frac{d_{\text{oxide}}RT \times P_{\mathrm{N}_2}}{P_{\text{oxide}} \times d_{\mathrm{N}_2}}
But doxide{d_{\text{oxide}}} = dN2d_{\mathrm{N}_2}
MoxideM_{\text{oxide}} = 5bar2bar\frac{5\,\text{bar}}{2\,\text{bar}} × 28 gmol1\mathrm{gmol}^{-1} = 70 gmol1\mathrm{gmol}^{-1}
© examsnet.com
Go to Question: