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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 13 of 67
Marks: +1, -0
What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n = 4 to an energy level with n = 2?
Solution:  
According to Rydberg equation, 1λ\frac{1}{\lambda} = R (1n12−1n22)\left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)
Here, n1n_1 = 2, n2n_2 = 4 and R = 109677 cm−1\mathrm{cm}^{-1}
1λ\frac{1}{\lambda} = 109677 (122−142)\left(\frac{1}{2^2} - \frac{1}{4^2}\right) = 009677 (14−116)\left(\frac{1}{4} - \frac{1}{16}\right) = 009677 4−116\frac{4-1}{16} = 109677 × 316cm−1\frac{3}{16} \mathrm{cm}^{-1}
⇒ λ = 16109677×3\frac{16}{109677 \times 3} = 16219031\frac{16}{219031} = 4.86 × 10−510^{-5} cm = 486 × 10−910^{-9} m = 486 nm
[Since 1 nm = 10−910^{-9} m]
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