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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 15 of 67
Marks: +1, -0
What is the maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state?
Solution:  
Maximum number of emission lines = n(n−1)2\frac{n(n-1)}{2}
= 6(6−1)2\frac{6(6-1)}{2} = 302\frac{30}{2} = 15 lines
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