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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 34 of 67
Marks: +1, -0
Calculate the energy required for the process, He(g)+\mathrm{He}^{+}_{(g)} → He2+(g)+e−{\mathrm{He}_2^{+}}_{(g)} + e^{-}.
The ionization energy for the H atom in the ground state is 2.18 × 10−18 J atom−110^{-18}\,\mathrm{J}\,\mathrm{atom}^{-1}.
Solution:  
Energy required = E∞−E1E_{\infty} - E_1 = − (−2.18×10−18n2×Z2)\left( -\frac{2.18\times10^{-18}}{n^2} \times Z^2 \right) = 2.18×10−18×2212\frac{2.18\times10^{-18}\times 2^2}{1^2}
= 8.72 × 10−18 J10^{-18}\,\mathrm{J}
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