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NCERT Class XI Chemistry Structure of Atom Solutions

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Question : 53 of 67
Marks: +1, -0
The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.
Solution:  
Energy of incident radiation (E) = hcλ\frac{hc}{\lambda}
= 6.626×10−34×3×108256.7×10−9\frac{6.626\times10^{-34}\times3\times10^{8}}{256.7\times10^{-9}} = 0.0774 × 10−1710^{-17} = 7.74 × 10−19 J10^{-19}\,\mathrm{J} = 4.83 eV
[Since 1.602 × 10−19 J10^{-19}\,\mathrm{J} = 1 eV]
The potential applied gives the kinetic energy to the electron.
Hence, K.E. of electron = 0.35 eV
∴ Work function = (4.83 – 0.35) eV = 4.48 eV
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