Test Index

NCERT Class XI Chemistry Structure of Atom Solutions

© examsnet.com
Question : 66 of 67
Marks: +1, -0
Indicate the number of unpaired electrons in :
(a) P,
(b) Si,
(c) Cr,
(d) Fe and
(e) Kr.
Solution:  
(a) 15P{}_{15}\mathrm{P} → 1s2 2s2 2p6 3s2 3p31s^2\,2s^2\,2p^6\,3s^2\,3p^3
Number of unpaired electrons = 3
(b) 14Si{}_{14}\mathrm{Si} → 1s2 2s2 2p6 3s2 3p21s^2\,2s^2\,2p^6\,3s^2\,3p^2
Number of unpaired electrons = 2
(c) 24Cr{}_{24}\mathrm{Cr} → 1s2 2s2 2p6 3s2 3p6 3d5 4s11s^2\,2s^2\,2p^6\,3s^2\,3p^6\,3d^5\,4s^1
Number of unpaired electrons = 6
(d) 26Fe{}_{26}\mathrm{Fe} → 1s2 2s2 2p6 3s2 3p6 3d6 4s21s^2\,2s^2\,2p^6\,3s^2\,3p^6\,3d^6\,4s^2
Number of unpaired electrons = 4
(e) 36Kr{}_{36}\mathrm{Kr} → 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p61s^2\,2s^2\,2p^6\,3s^2\,3p^6\,3d^{10}\,4s^2\,4p^6
Number of unpaired electrons = zero
© examsnet.com
Go to Question: