We have, z = i, i.e., z = 0 + 1⋅i Let 0 = r cosθ …(i) and 1 = r sinθ …(ii) Squaring and adding (i) and (ii), we get $r^2(\cos^2 \theta + \sin^2 \theta)$ = 1 ⇒ $r^2$ = 1 ⇒ r = 1 ∴ cosθ = 0, sinθ = 1 ⇒ cos θ = cos $\frac{\pi}{2}$ , sin θ = sin $\frac{\pi}{2}$ Here, cos θ = 0 and sin θ > 0 ∴ θ lies in first quadrant. ∴ θ = $\frac{\pi}{2}$ ∴ The required polar form is z = 1 $\left( \cos \frac{\pi}{2} + i \sin \frac{\pi}{2} \right)$