We have , $x^2$ - x + 2 = 0 Comparing the given equation with the general form $ax^2$ + bx + c = 0, we get a = 1, b = –1, c = 2. ∴ x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ = $\frac{1\pm\sqrt{(-1)^2-4\times1\times2}}{2}$ = $\frac{1\pm\sqrt{1-8}}{2}$ = $\frac{1\pm\sqrt{-7}}{2}$ = $\frac{1\pm i\sqrt{7}}{2}$ ∴ The roots of the given equation are $\frac{1+i\sqrt{7}}{2}$ and $\frac{1-i\sqrt{7}}{2}$