- 15 × 5 < $\frac{3(x-2)}{5}$ × 5 ≤ 0 × 5 [Multiplying by 5] ⇒ –75 < 3(x – 2) ≤ 0 ⇒ $\frac{-75}{3}$ < x - 2 ≤ $\frac{0}{3}$ [Dividing each side by 3] ⇒ –25 < x – 2 ≤ 0 or –25 + 2 < x – 2 + 2 ≤ 0 + 2 [Adding 2] ⇒ –23 < x ≤ 2 Hence, x is less than or equal to 2 and greater than –23, i.e., x ∈ (–23, 2]