(i) 3x – 7 > 2(x – 6) or 3x – 7 > 2x – 12 ⇒ 3x – 2x > –12 + 7 ⇒ x > –5 (ii) 6 – x > 11 – 2x ⇒ –x + 2x > 11 – 6 ⇒ x > 5 From (i) and (ii), we get x > 5 satisfies both the inequalities x > –5 and x > 5. ∴ Solution is (5, ∞)