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NCERT Class XI Mathematics - Trigonometric Functions - Solutions

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Question : 9 of 61
Marks: +1, -0
sin x = 35\frac{3}{5} , x lies in second quadrant.
Solution:  
sin x = 35\frac{3}{5} ⇒ cosec x = 53\frac{5}{3}
cos⁡2x\cos^2 x = 1 - sin⁡2x\sin^2 x ⇒ cos⁡2x\cos^2 x = 1 - 925\frac{9}{25} = 1625\frac{16}{25} ⇒ cos x = ± 45\frac{4}{5}
∴ cos x = - 45\frac{4}{5} [since x lies in second quadrant] ⇒ sec x = −54-\frac{5}{4}
∴ tan x = sin⁡xcos⁡x\frac{\sin x}{\cos x} = −34-\frac{3}{4} ⇒ cot x = −43-\frac{4}{3}
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