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Question : 2 of 14
Marks: +1, -0
Molar volume is the volume occupied by 1 mol of any (ideal) gas at standard temperature and pressure (STP : 1 atmospheric pressure, 0°C). Show that it is 22.4 litres.
Solution:  
Here, R=8.31Jmol1K1R = 8.31 \,\mathrm{J} \,\mathrm{mol}^{-1} \,\mathrm{K}^{-1}
T=0C=273K;n=1moleT = 0^{\circ}\mathrm{C} = 273 \,\mathrm{K}; n = 1 \,\mathrm{mole}
P=1atm=0.76P = 1 \,\mathrm{atm} = 0.76 of Hg\mathrm{Hg} column =0.76×13.6×103×9.8=1.013×105Nm2= 0.76 \times 13.6 \times 10^{3} \times 9.8 = 1.013 \times 10^{5} \,\mathrm{Nm}^{-2}
To prove V=22.4V = 22.4 litre
\therefore Using ideal gas equation PV=nRTP V = n R T
V=nRTP;V = \frac{n R T}{P} ;
V=1×8.31×2731.013×105V = \frac{1 \times 8.31 \times 273}{1.013 \times 10^{5}}
=22.4×103m3= 22.4 \times 10^{-3} \,\mathrm{m}^{3}
=22.4= 22.4 litres.
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