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Mechanical Properties of Fluids

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Question : 6 of 31
Marks: +1, -0
Toricelli’s barometer used mercury. Pascal duplicated it using French wine of density 984 kg m3^{-3}. Determine the height of the wine column for normal atmospheric pressure.
Solution:  
PP = Normal atmospheric pressure =1.013×105Pa= 1.013 \times 10^{5}\mathrm{Pa}
Let hh be the height of the French wine column which earth’s atmosphere can support.
∴ If PP' be the pressure corresponding to height h of wine column,
Then, P=hρwgP'=h \rho_{w} g
where ρw=\rho_{w} = density of wine =984kgm3=984 \mathrm{kg} \mathrm{m}^{-3}
Now according to given statement
P=PP'=P
or hρwg=Ph \rho_{w} g=P
or h=Pρwgh=\frac{P}{\rho_{w} g}
=1.013×105984×9.8=\frac{1.013 \times 10^{5}}{984 \times 9.8}
=10.5m=10.5 \mathrm{m}
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