A cricketer can throw a ball to a maximum ...

Motion in a Plane

Question : 16 of 32

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A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball?

Solution:

Here,

R_{\text{max}}=100\,\text{m}

Now,

R_{\text{max}}=\frac{u^2}{g}

u=\sqrt{R_{\text{max}}\times g}

u=\sqrt{100g}\,\text{m}\,\text{s}^{-1}

For vertical motion :

Initial velocity,

u=\sqrt{100g};

final velocity,

v=0

acceleration,

a=-g

Now,

v^2-u^2=2aS

H

is the maximum height attained, then

(0)^2-(\sqrt{100g})^2=2(-g)H

2gH=100g

H=\frac{100g}{2g}=50\,\text{m}

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