Test Index

Oscillations

© examsnet.com
Question : 4 of 25
Marks: +1, -0
Which of the following functions of time represent (a) simple harmonic, (b) periodic but not simple harmonic, and (c) non- periodic motion? Give period for each case of periodic motion (ω\omega is any positive constant):
(a) sinωtcosωt\sin \omega t - \cos \omega t
(b) sin3ωt\sin^{3} \omega t
(c) 3 cos(π42ωt)\cos \left( \frac{\pi}{4} - 2 \omega t \right)
(d) cosωt+cos3ωt+cos5ωt\cos \omega t + \cos 3 \omega t + \cos 5 \omega t
(e) exp(ω2t2)\exp \left( -\omega^{2} t^{2} \right)
(f) 1+ωt+ω2t21 + \omega t + \omega^{2} t^{2}
Solution:  
The function will represent a periodic motion, if it is identically repeated after a fixed interval of time and will represent simple harmonic motion, if it can be written uniquely in the form of a cos(2πTt+ϕ)\cos \left( \frac{2 \pi}{T} t + \phi \right) or sin(2πTt+ϕ)\sin \left( \frac{2 \pi}{T} t + \phi \right)whereT is the time period.
(a) sinωtcosωt\sin \omega t - \cos \omega t
=2(12sinωt12cosωt)= \sqrt{2} \left( \frac{1}{\sqrt{2}} \sin \omega t - \frac{1}{\sqrt{2}} \cos \omega t \right)
=2(sinωtcosπ4cosωtsinπ4)= \sqrt{2} \left( \sin \omega t \cos \frac{\pi}{4} - \cos \omega t \sin \frac{\pi}{4} \right)
=2sin(ωtπ4)= \sqrt{2} \sin \left( \omega t - \frac{\pi}{4} \right)
∴ It represents simple harmonicwith aperiod T=2πωT = \frac{2 \pi}{\omega} and a phase angle (π4).\left(-\frac{\pi}{4}\right).
(b) sin3ωt=14(3sinωtsin3ωt)\sin^{3} \omega t = \frac{1}{4} \left( 3 \sin \omega t - \sin 3 \omega t \right)
It represents periodic but not simple harmonic motion. Its time period is =2πω.= \frac{2 \pi}{\omega}.
(c) 3cos(π42ωt)=3cos(2ωtπ4)3 \cos \left( \frac{\pi}{4} - 2 \omega t \right) = 3 \cos \left( 2 \omega t - \frac{\pi}{4} \right)
It represents simple harmonic and its time period is 2π2ω=πω\frac{2 \pi}{2 \omega} = \frac{\pi}{\omega}
(d) cosωt+cos3ωt+cos5ωt\cos \omega t + \cos 3 \omega t + \cos 5 \omega t
It represents periodic but not simple harmonic motion. Its time period is 2πω\frac{2 \pi}{\omega} . It can be noted that each termrepresents a periodic function with a different angular frequency. Since period is the least interval of time after which a function repeats its value, cosωt\cos \omega t has a period T=2πωT = \frac{2 \pi}{\omega} , cos3ωt\cos 3 \omega t has a period 2π3ω\frac{2 \pi}{3 \omega} , cos5ωt\cos 5 \omega t has period 2π5ω=T5\frac{2 \pi}{5 \omega} = \frac{T}{5} , the last two forms repeat after any integral multiple of their period. Thus each term in the sum repeats itself after T, and hence the sum is a periodic function with a period 2πω\frac{2 \pi}{\omega}
(e) exp (ω2t2)(-\omega^{2} t^{2}) : It is an exponential function which decreases monotonically with increasing time and tends to zero as tt \rightarrow \infty and thus never repeats itself. Therefore it represents non-periodic motion.
(f) 1+ωt+ω2t21 + \omega t + \omega^{2} t^{2} It represents non-periodic motion (physically unacceptable because the function tends to infinity as tt \rightarrow \infty).
© examsnet.com
Go to Question: