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Thermodynamics

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Question : 10 of 10
Marks: +1, -0
A refrigerator is to maintain eatables kept inside at 9°C. If room temperature is 36°C, calculate the coefficient of performance.
Solution:  
Here, T1=36∘C=36+273=309 K,T_{1}=36^{\circ}\mathrm{C}=36+273=309\ \mathrm{K},
T2=9∘C=9+273=283 KT_{2}=9^{\circ}\mathrm{C}=9+273=283\ \mathrm{K}
Coefficient of performance of the refrigerator
=T2T1−T2=\frac{T_{2}}{T_{1}-T_{2}}
=282 K309 K−282 K=\frac{282\ \mathrm{K}}{309\ \mathrm{K}-282\ \mathrm{K}}
=282 K27 K=10.4=\frac{282\ \mathrm{K}}{27\ \mathrm{K}}=10.4
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