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Question : 26 of 33
Marks: +1, -0
It is claimed that two cesium clocks, if allowed to run for 100 years, free from any disturbance, may differ by only about 0.02 s. What does this imply for the accuracy of the standard cesium clock in measuring a time-interval of 1 s?
Solution:  
Here, the difference shown by two clocks in 100 years = 0.02 s
Therefore, the difference, the two clocks will show in 1s
=0.02 s100 years=\frac{0.02\,\mathrm{s}}{100\,\text{years}}
=0.02 s100×365×24×60×60 s=\frac{0.02\,\mathrm{s}}{100 \times 365 \times 24 \times 60 \times 60\,\mathrm{s}}
=6.34×10−12 s≃10−11 s=6.34 \times 10^{-12}\,\mathrm{s} \simeq 10^{-11}\,\mathrm{s}
Therefore, accuracy shown by the atomic clock = 10−11 s10^{-11}\,\mathrm{s} in 1 s or 1 s in 101110^{11} s.
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