(a) Inductive reactance, $X_L$ = 2πfL $X_L$ = 2π(50) 80 × $10^{-3}$ = 25.12 Ω Capacitive reactance, $X_C$ = $\frac{1}{2\pi fC}$ $X_C$ = $\frac{1}{2 \times 3.14 \times 50 \times 60 \times 10^{-6}}$ = 53.05 Ω Impedance = $X_C - X_L$ = 53.05 – 25.12 = 27.93 Ω rms value of current, $I_v$ = $\frac{E_v}{Z}$ = $\frac{230}{27.93}$ = 8.235 A Peak value $I_0$ = $I_v \sqrt{2}$ = 11.644 A (b) Potential drop across L, $V_L$ = $I_v X_L$ = 206.68 V Potential drop across C, $V_C$ = $I_v X_C$ = 436.87 V (c) Average power transferred to inductor is zero, because of phase difference π/2. P = $E_v I_v$ cos ϕ ϕ = π/2, ∴ P = 0 (d) Average power transferred to capacitor is also zero, because of phase difference π/2. P = $E_v I_v$ cos ϕ ϕ = π/2, ∴ P = 0 (c) Total power absorbed by the circuit $P_{\text{Total}}$ = $P_L + P_C$ = 0