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NCERT Class XII Chapter
Electrostatic Potential and Capacitance
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Question : 5 of 37
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A parallel plate capacitor with air between the plates has a capacitance of 8 pF. What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
Solution:  
C0C_0 = ε0Ad\frac{\varepsilon_0 A}{d} = 8 pF
C = Kε0Ad2\frac{K\varepsilon_0 A}{\frac{d}{2}} = 2Kε0Ad\frac{2K\varepsilon_0 A}{d} = 2KC02KC_0 = 2 × 6 × 8 pF or C = 96 pF
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