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NCERT Class XII Chemistry
Chapter - Alcohols, Phenols and Ethers
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Question : 26 of 45
Marks: +1, -0
How is 1-propoxypropane synthesised from propan-1-ol? Write mechanism of this reaction.
Solution:  
CH3CH2CH2OHPropanol→?(CH3CH2CH2)2OPropoxypropane\underset{\text{Propanol}}{\mathrm{CH_3CH_2CH_2OH}} \xrightarrow{?} \underset{\text{Propoxypropane}}{(\mathrm{CH_3CH_2CH_2})_2\mathrm{O}}
This reaction can be brought about as:
CH3CH2CH2OHPropanol+SOCl2+→CH3CH2CH2Cl+SO2+HCl\underset{\text{Propanol}}{\mathrm{CH_3CH_2CH_2OH}} + \mathrm{SOCl}_2 + \rightarrow \mathrm{CH_3CH_2CH_2Cl} + \mathrm{SO}_2 + \mathrm{HCl}
2CH3CH2CH2OH+2Nametal→⊖CH3CH2CH2ONa⊕+H22\mathrm{CH_3CH_2CH_2OH} + \underset{\text{metal}}{2\mathrm{Na}} \overset{\ominus}{\rightarrow} \mathrm{CH_3CH_2CH_2O}\overset{\oplus}{\mathrm{Na}} + \mathrm{H}_2
CH3CH2CH2Cl1-Chloropropane+CH3CH2CH2O⊖Na⊕Sodium propoxide→(CH3CH2CH2)2OPropoxypropane\underset{\text{1-Chloropropane}}{\mathrm{CH_3CH_2CH_2Cl}} + \underset{\text{Sodium propoxide}}{{\overset{\ominus}{\mathrm{CH_3CH_2CH_2O}} \overset{\oplus}{\mathrm{Na}}}} \rightarrow \underset{\text{Propoxypropane}}{(\mathrm{CH_3CH_2CH_2})_2\mathrm{O}}
Mechanism : SN2S_N2 attack of propoxide on the halide
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