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NCERT Class XII Chemistry
Chapter - Electrochemistry
Questions with Solutions

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Question : 30 of 32
Marks: +1, -0
Consider the reaction: Cr2O72+14H++6e2Cr3++7H2O\mathrm{Cr}_2\mathrm{O}_7^{2-} + 14\mathrm{H}^{+} + 6e^{-} \rightarrow 2\mathrm{Cr}^{3+} + 7\mathrm{H}_2\mathrm{O}
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72\mathrm{Cr}_2\mathrm{O}_7^{2-} ?
Solution:  
Cr2O72+14H++6e2Cr3++7H2O,\mathrm{Cr}_2\mathrm{O}_7^{2-} + 14\mathrm{H}^{+} + 6e^{-} \rightarrow 2\mathrm{Cr}^{3+} + 7\mathrm{H}_2\mathrm{O},
6×96500C=579000C6 \times 96500 \, \text{C} = 579000 \, \text{C} of electricity is required to reduce 1 mol of Cr2O72\mathrm{Cr}_2\mathrm{O}_7^{2-}.
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