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NCERT Class XII Chemistry
Chapter - The p-Block Elements
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Question : 35 of 74
Marks: +1, -0
How are XeO3\mathrm{XeO}_3 and XeOF4\mathrm{XeOF}_4prepared?
Solution:  
Hydrolysis of XeF4\mathrm{XeF}_4 and XeF6\mathrm{XeF}_6 with water gives XeF3\mathrm{XeF}_3 .
6XeF4+12H2O→4Xe+2XeO3+24HF+3O26\mathrm{XeF}_4 + 12\mathrm{H}_2\mathrm{O} \rightarrow 4\mathrm{Xe} + 2\mathrm{XeO}_3 + 24\mathrm{HF} + 3\mathrm{O}_2
XeF6+3H2O→XeO3+6HF\mathrm{XeF}_6 + 3\mathrm{H}_2\mathrm{O} \rightarrow \mathrm{XeO}_3 + 6\mathrm{HF}
Partial hydrolysis of XeF6\mathrm{XeF}_6 gives oxyfluorides, XeOF4\mathrm{XeOF}_4 and XeO2F2\mathrm{XeO}_2\mathrm{F}_2.
XeF6+H2O→XeOF4+2HF\mathrm{XeF}_6 + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{XeOF}_4 + 2\mathrm{HF}
XeF6+2H2O→XeO2F2+4HF\mathrm{XeF}_6 + 2\mathrm{H}_2\mathrm{O} \rightarrow \mathrm{XeO}_2\mathrm{F}_2 + 4\mathrm{HF}
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