The given plane is 5y + 8 = 0 ...(1)Direction ratios of the normal to the plane are < 0, 5, 0 >∴ Direction cosines of the normal to the plane are < 0, 1, 0 >And distance of (1) from the origin $=\frac{\left|0+8\right|}{\sqrt{0+25+0}}=\frac{8}{5}$