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AIEEE 2011 Solved Paper
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© examsnet.com
Question : 1
Total: 91
A gas absorbs a photon of
355
nm
and emits at two wavelengths. If one of the emissions is at
680
nm
, the other is at:
325 nm
743 nm
518 nm
1035 nm
Validate
Solution:
Here a photon is divided into two photons of different wavelength.
According to the law of conservation of energy,
Energy of photon before dividing into two parts = Energy of first photon + Energy of second photon
h
c
λ
=
h
c
λ
1
+
h
c
λ
2
⇒
1
λ
=
1
λ
1
+
1
λ
2
⇒
1
355
=
1
680
+
1
λ
2
λ
2
=
742.77
nm
=
743
nm
© examsnet.com
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