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BITSAT 2018 Slot 2 Solved Paper
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© examsnet.com
Question : 1
Total: 150
PART I
Physics
Two inductors
L
1
and
L
2
are connected in parallel and a time varying current flows as shown in figure. The ratio of current
i
1
i
2
at any time
t
is
L
2
L
1
L
1
L
2
L
2
2
(
L
1
+
L
2
)
2
L
1
2
(
L
1
+
L
2
)
2
Validate
Solution:
As the inductors are in parallel, induced emf across the two inductors is the same, i.e.
e
1
=
e
2
L
1
(
d
i
1
d
t
)
=
L
2
(
d
i
2
d
t
)
On integrating both sides, we get
L
1
∫
d
i
1
d
t
=
L
2
∫
d
i
2
d
t
L
1
i
i
=
L
2
i
2
⇒
i
1
i
2
=
L
2
L
1
© examsnet.com
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