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JEE Advanced 2020 Concept Recapitulation Test 4 Paper 2

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If a narrow beam of light falls on a glass hemisphere of refraction index 2 as shown in the figure. Then the image formed.

Due to first surface has co-ordinates (−√2R,−√2R)
Due to first surface has co-ordinates (−√3R,−√3R)
Due to second surface has co-ordinates (−R∕√2,R∕√2)
Due to second surface has co-ordinates (−R∕√3,R∕√3)

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