Let f : R - {-4/3} → R' - {4/3} be a function defined as f (x) = 4x/3x+4. The inverse of f is the map g : R - {4/3} → R - {-4/3} is given by:

Correct Answer is : g (y) = 4y4−3y4y/4-3y4−3y4y

Let f : R - {-4/3} → R' - {4/3} be a function defined as f (x) = 4x/3x+4. The inverse of f is the map g : R - {4/3} → R - {-4/3} is given by:

Correct Answer is : g (y) = 4y4−3y4y/4-3y4−3y4y

Test Index

JEE Mains 2020 Model Paper 1 New Pattern

MATHEMATICS

(SINGLE CORRECT ANSWER TYPE)

This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct.

Question : 1 of 75

Marks: +1, -0

Let f : R - {-4/3} → R' - {4/3} be a function defined as f (x) =

\frac{4x}{3x+4}

. The inverse of f is the map g : R - {4/3} → R - {-4/3} is given by:

g (y) = $\frac{3y}{3-4y}$
g (y) = $\frac{4y}{4-3y}$
g (y) = $\frac{4y}{3-4y}$
g (y) = $\frac{3y}{4-3y}$

Validate

Solution:

As f is one - one and onto , so f is invertible.

f (x) =

\frac{4x}{3x+4}

, x ∊ R -

\left\{ \frac{-4}{3} \right\}

Now, y =

\frac{4x}{3x+4}

⇒ 3xy + 4y = 4x ⇒ (4 - 3y) x = 4y

∴ g (y) =

\frac{4y}{4-3y}

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