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Test Index
KEAM 2015 Physics and Chemistry Paper
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© examsnet.com
Question : 1
Total: 120
A ray of light is incident normally on one refracting surface of an equilateral prism. If the refractive index of the material of the prism is 1.5, then
the emergent ray is deviated by 30°
the emergent ray is deviated by 60°
the emergent ray just graces the second reflecting surface
the ray undergoes total internal reflection at second refracting surface
the ray emerges normally from the second refracting surface
Validate
Solution:
Key Concept The ratio of sine of the angle of incidence to sine of angle of refraction
(
I
)
is a constant called refractive index.
i.e.
sin
i
sin
I
=
µ
(a constant). For two media, Snell's law can be written as,
1
µ
2
=
µ
2
µ
1
=
sin
i
sin
I
Given, refractive index of a prism
n
=
1.5
=
3
2
As
µ
=
1
sin
θ
⇒
µ
=
1
sin
60
∘
µ
=
2
√
3
⇒
sin
C
=
1
n
sin
C
=
2
3
⇒
C
=
sin
−
1
2
3
C
=
42
∘
Angle of incidence
>
critical angle
So, total internal reflection takes places at second refracting surface.
© examsnet.com
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