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KEAM 2019 Math Paper
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© examsnet.com
Question : 1
Total: 121
If
r
=
3
i
+
2
j
−
5
k
,
a
=
2
i
−
j
+
k
b
=
i
+
3
j
−
2
k
and
c
=
−
2
i
+
j
−
3
k
such that
r
=
λ
a
+
µ
b
+
γ
c
then
µ
,
γ
,
λ
are in
G
P
λ
,
µ
,
γ
are in
H
P
λ
µ
,
γ
are in
A
P
µ
,
λ
2
,
γ
are in AP
None of these
Validate
Solution:
A
s
,
3
i
+
2
j
−
5
k
=
λ
(
2
i
−
j
+
k
)
+
µ
(
i
+
3
j
−
2
k
)
+
γ
(
−
2
i
+
j
−
3
k
)
⇒
3
=
2
λ
+
µ
−
2
γ
,
2
=
−
λ
+
3
µ
+
γ
−
5
=
λ
−
2
µ
−
3
γ
On solving we get,
µ
=
1
,
γ
=
2
λ
=
3
∴
µ
,
λ
2
,
γ
i.e.
1
,
3
2
,
2
are in AP.
© examsnet.com
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