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KVPY SA Exam 2014 Question Paper
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© examsnet.com
Question : 1
Total: 80
PART-I
MATHEMATICS
Let r be a root of the equation
r
2
+
2
r
+
6
=
0
. The valueof
(
r
+
2
)
(
r
+
3
)
(
r
+
4
)
(
r
+
5
)
is equal to
51
-51
-126
12
Validate
Solution:
r is root, therefore
r
2
+
2
r
+
6
=
0
(
r
+
2
)
(
r
+
3
)
(
r
+
4
)
(
r
+
5
)
=
(
r
2
+
2
r
+
6
+
3
r
)
(
r
2
+
4
r
+
5
r
+
20
)
=
(
3
r
)
(
7
r
+
14
)
=
21
(
r
2
+
2
r
)
=
21
(
−
6
)
=
−
126
© examsnet.com
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