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NEET Exam Model Paper 6
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© examsnet.com
Question : 1
Total: 180
The base resistance
R
B
in the circuit,is (given
β
=
90
,
V
CE
=
4
V
,
V
BE
=
0.7
V
10
k
Ω
82
k
Ω
100
k
Ω
0.82
k
Ω
Validate
Solution:
Applying loop law at output port,
9
−
4
=
I
C
R
C
;
I
C
=
2.5
m
A
I
B
=
I
C
β
=
2.5
90
=
2.78
×
10
−
5
A
=
27.8
µ
A
Since, the transistor operates in active region, therefore
V
BE
=
0.7
V
Applying loop law at input circuit,
I
B
=
3
−
0.7
R
B
R
B
=
2.3
×
10
5
2.78
=
82
k
Ω
© examsnet.com
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