Concept:The sum and product of variables can be linked using standard algebraic identities for squares and cubes.Explanation:Given a+b+c=6, a2+b2+c2=14, and a3+b3+c3=36.Use the identity (a+b+c)2=a2+b2+c2+2(ab+bc+ca).Substitute the values: 62=14+2(ab+bc+ca).So, 36=14+2(ab+bc+ca).Thus, 2(ab+bc+ca)=22, giving ab+bc+ca=11.Now use a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca).Substitute: 36−3abc=6(14−11).So, 36−3abc=18.Then, 3abc=18.Hence, abc=6.Answer:abc=6, so option B is correct.