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Mensuration Practice Test 9
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© examsnet.com
Question : 1
Total: 40
If ΔABC is similar to ΔDEF such that BC = 3 cm, EF = 4 cm and area of ΔABC = 54
c
m
2
, then the area of ΔDEF is:
78
c
m
2
96
c
m
2
54
c
m
2
66
c
m
2
Validate
Solution:
Area of ΔABC = 54
c
m
2
b × h = 54
c
m
2
3 × h = 54
h =
54
3
= 18 cm
ΔABC is similar to ΔDEF
⇒
b
h
:
b
1
h
1
3
18
:
4
h
h
= 24 cm
Area of ΔDEF = b × h
4 × 24 = 96
c
m
2
© examsnet.com
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