RRB ALP CBT I 16 Feb 2026 Shift 2 Paper

Concept:HCF is the largest number that divides all given numbers without leaving any remainder.Explanation:Write each number as a product of its prime factors.$24 = 2^3 \times 3$$36 = 2^2 \times 3^2$$102 = 2 \times 3 \times 17$The common prime factors in all three numbers are $2$ and $3$.Take the lowest power of each common factor: $2^1$ and $3^1$.Multiply these to get the HCF: $2 \times 3 = 6$.Therefore, the HCF of 24, 36 and 102 is 6.As a quick check, $6$ divides $24$, $36$ and $102$ exactly: $24 \div 6 = 4$, $36 \div 6 = 6$, $102 \div 6 = 17$.Answer:Option B — 6