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UPSC NDA I 2011 Mathematics Paper
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© examsnet.com
Question : 1
Total: 120
What is the value of the determinant
|
x
+
1
x
+
2
x
+
4
x
+
3
x
+
5
x
+
8
x
+
7
x
+
10
x
+
14
|
?
x
+
2
x
2
+
2
2
−
2
Validate
Solution:
|
x
+
1
x
+
2
x
+
4
x
+
3
x
+
5
x
+
5
x
+
7
x
+
10
x
+
14
|
c
1
→
c
2
−
c
1
,
c
3
−
c
2
=
|
−
1
−
2
x
+
4
−
2
−
3
x
+
8
−
3
−
4
x
+
14
|
=
|
1
2
x
+
4
2
3
x
+
8
3
4
x
+
14
|
=
R
2
−
R
1
,
R
3
−
R
2
|
1
2
x
+
4
1
1
4
1
1
6
|
R
1
−
R
2
,
R
2
−
R
3
|
0
1
x
0
0
−
2
1
1
6
|
=
1
{
(
−
2
)
}
=
−
2
.
© examsnet.com
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