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CBSE Class 10 Science 2015 Term II Outside Delhi Set 1

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Question : 22 of 36
Marks: +1, -0
What is meant by power of a lens? Define its S.I. unit.
You have two lenses AA and BB of focal lengths +10 cm+10\,\text{cm} and −10 cm-10\,\text{cm} respectively. State the nature and power of each lens. Which of the two lenses will form a virtual and magnified image of an object placed 8 cm8\,\text{cm} from the lens? Draw a ray diagram to justify your answer.
Solution:  
Power of a lens is defined as the ability of lens to converge or to diverge a beam of light. It is also defined as reciprocal of focal length in metres.
For lens A :
fA=+10 cm=0.1 mf_{A}=+10\,\text{cm}=0.1\,\text{m}
Since the focal length is positive, it is a convex lens.
Now, PA=  1fA=  10.1=+10 DP_{A}=\;\frac{1}{f_{A}}=\;\frac{1}{0.1}=+10\,\text{D}.
For lens B :
fB=−10 cm=−0.1 mf_{B}=-10\,\text{cm}=-0.1\,\text{m}
Since the focal length is negative, it is a concave lens.
PB=  1fB=  1−0.1=−10 DP_{B}=\;\frac{1}{f_{B}}=\;\frac{1}{-0.1}=-10\,\text{D}
In case of a convex lens, image is virtual and magnified if object is placed between focus and optical centre.
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