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CBSE Class 10 Science 2015 Term II Outside Delhi Set 1

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Question : 23 of 36
Marks: +1, -0
One half of a convex lens of focal length 10 cm is covered with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm30\text{ cm} from the lens? Draw a ray diagram to justify your answer. A 4 cm4\text{ cm} tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm20\text{ cm}. The distance of the object from the lens is 15 cm15\text{ cm}. Find the nature, position and size of the image.
Solution:  
Yes, it can produce an image of a complete object placed at a distance of 30 cm30\text{ cm} from the lens.
Given : h1=4 cm,  f=+20 cm,  u=−15 cmh_1=4\text{ cm},\; f=+20\text{ cm},\; u=-15\text{ cm}
We know that,
  1f=  1v−  1u\;\frac{1}{f}= \;\frac{1}{v}- \;\frac{1}{u}
  1v=  1f+  1u=  120      115=  3460=  160\;\frac{1}{v}= \;\frac{1}{f}+ \;\frac{1}{u}= \;\frac{1}{20} \;\; \;\frac{1}{15}= \;\frac{34}{60}= \;\frac{1}{60}
∴\therefore Image distance, v=−60 cmv=-60\text{ cm}.
Image will be virtual, erect and placed in the direction of the object.
Now, Magnification, m=  h2h1=  vum=\;\frac{h_2}{h_1}=\;\frac{v}{u}
h2=  vu×h1=  −60−15×4=+16 cm.h_2=\;\frac{v}{u} \times h_1=\;\frac{-60}{-15} \times 4=+16\text{ cm} .
The size of the image is 16 cm16\text{ cm}.
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