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Question : 24
Total: 30
(a) Write the mathematical expression for Joule's law of heating.
(b) Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of40 V .
(b) Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of
Solution:
(a) According to the Joule's law of heating, heat produced in a resistor is directly proportional to the :
(i) square of current (I) for a given resistance.
(ii) resistance (R) for a given current.
(iii) the time (t ) for which the current. flows through the resistor.
Mathematical form of Joule's law of heating is :
H = I 2 R t
(b) Given, charge( q ) = 96000 C
Time( t ) = 2 hrs = 120 min = 7200 s
Potential difference( V ) = 40 volt
We know that,
Heat( H ) = V It, where I is current...(i)
Also,
I = q ∕ t , where q is charge and t is time in seconds.....(ii)
∴ By putting I = q ∕ t in eqn. (1) we get,
H = ( V × q ∕ t ) × t = V q t ∕ t = V q
⇒ H = 40 × 96000 joule
⇒ H = 3840000 joule
(i) square of current (I) for a given resistance.
(ii) resistance (R) for a given current.
(iii) the time (
Mathematical form of Joule's law of heating is :
(b) Given, charge
Time
Potential difference
We know that,
Heat
Also,
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